Determine the equation of the perpendicular bisector of a segment with endpoints (–3, –1) and (3, 5).

y = -x + 2.

Step-by-step explanation:

The slope of the line joining the 2 points = (5 - -1)/(3- -3)

= 6/6 = 1

So the slope of the perpendicular bisector = -1/1 = -1.

The centre of the line segment is at the point (-3+3)/2,  (-1+5)/2

= (0, 2)

So the required equation is:

y - 2 = -1(x - 0)

y - 2 = -x

y = -x + 2.

(2x + 16) + (x) = 180

step-by-step explanation:

given,

abcd is a quadrilateral inscribed in a circle

angle a is labeled x plus 16, (x + 16)

angle b is labeled x degrees, (x)

angle c is labeled 6x minus 4, (6x – 4)

angle d is labeled 2x plus 16, (2x + 16)

what equation can be used to solve for angle b?

we know that the sum of the opposite angles of a simple quadrilateral inscribed in a circle is 180 degrees.

angle b is opposite angle d

therefore, angle b + angle d = 180

(x) + (2x + 16) = 180 

same as (2x + 16) + (x) = 180

y = i/2 xtnop + (3i/2 tnop+ 1)

step-by-step explanation:

the picture is the step by step explanation.