If person a and person b go fishing and both catch fish. If person a gives half their fish to person b and then they have equal amounts. How many fish does each have

The number of fishes person b initially has is 0

The number of fishes person a initially has is x, where x is any natural number

Step-by-step explanation:

The given parameters are;

let x represent the number of fish person a catches and let y represent the number of fishes that person b catches, we have;

x - x/2 = y + x/2

2·x - x = 2·y + x

2·x = 2·y + 2·x

∴ y = 0

Therefore;

The number of fishes person b initially has = 0

The number of fishes person a initially has = x, where x is any natural number.

he kicked it up? is this the answer ?

step-by-step explanation:

a_n = a_1 + (n - 1)d

the first term is 6.

the common difference d = ?

when you find d, replace n with 7 and d with the common difference to find your answer.