Find the equation of a line parallel to y = 3x - 6, passing through the point (-6, -7). y = 3x + 11

y = 3x - 11

y = 3x - 7

y = -1/3x - 9

Parallel lines have the same a slope. Therefore if

k: y = 3x - 6 → slope = 3

and l: y = mx + b

l || k ⇔ m = 3

l: y = 3x + b

We have the point (-6, -7). Put the coordinates to the equation:

-7 = 3(-6) + b

-7 = -18 + b    add 18 to both sides

11 = b → b = 11

y = 3x + 11

3< x< 5

step-by-step explanation:

|x - 4| < 1

there are two solutions, one positive and one negative.   remember to flip the inequality when taking the negative solution

x-4 < 1       x-4 > -1

add 4 to each side

x-4+4 < 1+4       x-4+4 > -1+4

x< 5                 x> 3

3< x< 5