How many solutions does the system of equations below have?
y = 3x + 4
y + 6 = 3x

0 / no solutions

Step-by-step explanation:

Rewrite both in terms to the form y = equation.

EQ1: y = 3x + 4 (already in correct form)

EQ2: y = 3x - 6 (subtracting 6 from both sides).

Now suppose there is an intersection, then:

3x + 4 = 3x - 6, subtracting 3x from both sides gives:

4 = -6, which is a contradiction!

Therefore there are 0 / no solutions

attachment?

step-by-step explanation:

answer: c, the green line

step-by-step explanation:

there is no black line, eliminate b.

simple interest implies periodic payments, but the red line shows no payments, eliminate d.

simple interest has equal payments. if paid say every day, the graph is about a straight line (actually a stairstep).

the yellow line is not straight, eliminate a.

check: the green line is straight, answer is c.

simple interest with positive interest rate gives a straight line sloping up to the right. green line:

g(t) = $100 + ($200-$100) ÷ (20 years) × (t years)

= $100 + (4%/year) × ($100)(t years)

incidentally, the yellow line curving upward represents continuously compounded interest

y = $100 × 2^(t years / (14 assuming the yellow line hits $200 at 14 years. 2^0 is 1, so y(0) = $100; 2^(14/14) is 2, so y(14) = $200.