The HCF of two numbers is 20. The LCM of both numbers is a multiple of 14. One number is greater than the other, work out the smallest possible numbers

20

Step-by-step explanation:

Given that the HCF of two numbers is 20 and the LCM of both numbers is a multiple of 14.

So, the LCM of both numbers = 14n where n can be any natural number.

As HCF of two numbers is always smaller than or equal to the smallest number among both the numbers.

Here, the HCF of two numbers is 20, so the smallest number is greater than of equal to 20.

Hence, the smallest possible number is 20.

d. 8

step-by-step explanation:

the given radical expression is:

we can rewrite this as:

we express as square numbers to get;

the exponents will now cancel out to give.

the correct answer is d

she would want to sell 10 full-year subscriptions and at least 9 half-year subscriptions to get a total of at least $300. 

i hope this answer you! if you have any further questions or concerns, feel free to ask! : )

step-by-step explanation:

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