![In\: \triangle BDC, \\\\BD = CD.... (given) \\\\\therefore m\angle DBC =m\angle DCB\\(By\: isosceles \:\triangle\: property) \\\therefore a\degree = b\degree.... (1)\\\\m\angle BDC= 90\degree \\\\\because m\angle BDC + a\degree + b\degree=180\degree \\\\90\degree+ a\degree + a\degree=180\degree\\ [from \: equation \: (1)]\\\\2a\degree=180\degree -90\degree\\2a\degree= 90\degree\\\\\therefore a\degree=\frac{ 90\degree}{2} \\\\\huge\purple {\boxed {\therefore a\degree=45\degree}} \\\\\implies \huge\red {\boxed { b\degree=45\degree}} \\\\In\: \triangle ABC, \\\\AB = BC.... (given) \\\\\therefore m\angle BAC =m\angle BCA\\(By\: isosceles \:\triangle\: property) \\\therefore c\degree = b\degree\\\\\because b\degree=45\degree \\\\\implies \huge\orange {\boxed { b\degree=45\degree}} [](/tpl/images/1009/1124/df47e.png)
of a°, bº and cº.
Mathematics, 29.12.2020 17:50 nichelle2807
1) In the given ABC; AB = BC and BD =
BC and BD = CD. Find the value
of a°, bº and cº.
Answers: 1
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You know the right answer?
1) In the given ABC; AB = BC and BD =
BC and BD = CD. Find the value
of a°, bº and cº.
of a°, bº and cº.
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