On a large scale farm there are 6 more pigs than cows,4 times as many goats as pigs and two-thirds as many sheep As goats (a)if there r y cows write down a simplified expression in y for the total number of animals
(b)find the total number of animals given that there are 112 sheeps

cows = y

pigs = y + 6

goats = 4(y+6) = 4y+ 24

sheep = 2/3 * (4y + 24) = 8/3y + 16

sol.

total

= y+y+6+4y+24+8/3y+16

=26/3y + 46

sheep = 112 = 8/3 y + 16

8/3y = 112-16

y= (112 - 16)*3/8

y = 36

then substitute y with 36 in the total equation so yeah...

36+36+6+4(36)+24+8/3(36)+16

=358 animals

check above link.

graphically?   well, you graph them both, the solutions is where they both intersect each other, since there are two solutions, meaning they will meet twice, or namely the linear will run into the quadratic curve twice, and where they meet, those x,y coordinates are the solutions to the system.