Determine the two ordered pair solutions of the equation , given (2, ), and (-6, ).

We conclude that the two ordered pairs (0, 0) and (-2, 2) are the solutions of the equation y = 2x² + 3x.

Step-by-step explanation:

Given the expression

y = 2x² + 3x

Substituting x = 0

y = 2(0)² + 3(0)

y = 0+0

y = 0

Thus, the ordered pair is: (0, 0)

Now, substituting x = -2

y = 2x² + 3x

y = 2(-2)² + 3(-2)

y = 8 - 6

y = 2

Thus, the ordered pair is: (-2, 2)

Therefore, we conclude that the two ordered pairs (0, 0) and (-2, 2) are the solutions of the equation y = 2x² + 3x.

the polynomial is a perfect square trinomial of the form a^2-2ab+b^2:

option a. true

step-by-step explanation:

9x^2-12x+4

comparing with the form a^2-2ab+b^2

1.) a^2=9x^2

solving for a: square root both sides of the equation:

sqrt(a^2)=sqrt(9x^2)

a=sqrt(9) sqrt(x^2)

a=3x

2.) b^2=4

solving for b: square root both sides of the equation:

sqrt(b^2)=sqrt(4)

b=2

to be a perfet square trinomial 2ab must be equal to 12x. let's check:

2ab = 2 (3x) (2)

2ab = 12x

correct