. Find four consecutive odd integers such that the sum of the first and fourth is 55 greater than the opposite of the third.

The four consecutive odd integers = 15, 17, 19, 21

Step-by-step explanation:

Four consecutive odd integers in Mathematics when x is an integer is given as:

x , x + 2 , x + 4, x + 6

Where:.

First integer = x

Second integer = x + 2

Third integer = x + 4

Fourth integer = x + 6

The sum of the first and fourth is 55 greater than the opposite of the third

Hence :

x + x + 6 = -(x + 4) + 55

x + x+6 = (-x - 4) + 55

2x + 6 = -x + 51

Collect like terms

2x + x = 51 - 6

3x = 45

x = 15

Therefore,

First integer = x = 15

Second integer = x + 2 = 15 + 2 = 17

Third integer = x + 4 = 15 + 4 = 19

Fourth integer = x + 6 = 15 + 6 = 21

The four consecutive odd integers = 15, 17, 19, 21

the correct answer is 45x

9×5=45 then add the x

a)(x-2)^2+(y-1)^2=9

step-by-step explanation:

(picture explains)