celia rides the downtown trolley three times every day. there are five trolleys that run on the loop downtown. what is the probability that celia will rise the number two trolley on all three trips today?

The correct format of the question is as follows

Celia rides the downtown trolley three times every day. there are five trolleys that run on the loop downtown. what is the probability that Celia will ride the number two(#2) trolley on all three trips today?

The probability that Celia will be selecting the number two ride for the entire three trips for that day will be 1/125.

Step-by-step explanation:

Celia rides to downtown trolley three times a day everyday, there are five available choices for Celia that means she has five trolleys through which she can travel.

We are asked that we need to use the #2 trolley for all the three rides for that day.

Probability for choosing the #2 ride = 1/5 (as there are five available choices and we   need to select only the no 2)

Also we need this #2 ride for all the three rides that means we will be selecting the #2 ride thrice

so our required probability will be = 1/5*1/5*1/5

                                        = (1/5)^3

                                        = 1/125

Therefore the probability that Celia will be selecting the number two ride for the entire three trips for that day will be 1/125.

step-by-step explanation:

because 1/3 is a fraction. we can tell because there is a divisor symbol between the 1 and the 3. if we were to add 2 fractions together, we would add the numerators, which is the number on top, but not the denominators, which is the number on the bottom

1/3+1/3=2/3

hope this !