The first blanks options are -2 , -1/2 , 2 , 1/2 The seconds are -5 , -3 , 5, 3
the thirds are -2, -1, 2, 1
and the fourths are -2, -1, 2, 1

equation 1

y = -2x

equation 2

y = x-3

Solution to both

(1,-2)

Step-by-step explanation:

We need to get the equations of both lines

General form is;

y = mx + c

where m is slope and c is the y-intercept

Table 1

since we have a point 0,0; the y-intercept here is zero

Let us get the slope. We can do this by selecting any two points

m = (y2-y1)/(x2-x1)

m = (2-10)/(-1+5) = -8/4 = -2

So the equation of the first line is;

y = -2x

Table 2

we get the slope

m = (4+2)/(7-1) = 6/6 = 1

The partial equation is;

y = x + c

To get c, we select any two point and substitute

4 = 7 + c

c = 4-7

c = -3

So the equation is;

y = x-3

To get the solution to both systems, we equate the y

-2x = x - 3

-2x-x = -3

-3x = -3

x = -3/-3

x = 1

To get y, we substitute;

recall; y = -2x

y = -2(1)

y = -2

Solution to the system is;

(1,-2)