Write two numbers which his greatest common divisor is 210 and to be between 10000 and 11000

  10080, 10290

Step-by-step explanation:

The multipliers of 210 required will be mutually prime integers that satisfy ...

  10000 ≤ 210n ≤ 11000

  47.61 ≤ n ≤ 52.38

That is, you want a pair of integers, each between 48 and 52, that have no common factors. Possibilities include ...

  (48, 49), (49, 50), (49, 51), (49, 52), (50, 51), (51, 52)

For the above numbers, we have chosen ...

  48×210 = 10,080

  49×210 = 10,290

answer: 38.47 is your answer

step-by-step explanation: hope i you and who ever sees this answer have a great rest of your day : )