Two cross roads, each of width 10 m, cut a right angles through the centre of a rectangular park of length 700 m and breadth 300 m and parallel to its sides. Find the area of the roads. Also find the area of the park excluding cross roads. Give the answer in hectares.

The answer is below

Step-by-step explanation:

The above problem is represented in the image below.

a) To find the area of the cross roads, we use the formula:

Area of cross roads = area of EFGH + area of IJKL - area of PQRS.

Area of rectangle = length * breadth; area of square = length * length

Rectangle EFGH = 300 m by 10 m;

Area of Rectangle EFGH = 300 m * 10 m = 3000 m²

Rectangle IJKL = 700 m by 10 m;

Area of Rectangle EFGH = 700 m * 10 m = 7000 m²

Square PQRS = 10 m by 10 m;

Area of Square PQRS = 10 m * 10 m = 100 m²

Area of cross roads = area of EFGH + area of IJKL - area of PQRS

Area of cross roads = 3000 m² + 7000 m² - 100 m² = 9900 m²

Area of cross roads = 9900 m²

1 hectare = 10000 m². Hence:

Area of cross roads = 9900 m² * (1 hectare / 10000 m²) = 0.99 hectare

Area of cross roads = 0.99 hectare

b) Area of the park excluding cross roads = Area of rectangle ABCD - Area of cross roads

Rectangle ABCD = 700 m by 300 m;

Area of Rectangle ABCD = 700 m * 300 m = 210000 m²

Therefore, substituting:

Area of the park excluding cross roads = 210000 m² - 9900 m² = 200100 m²

Area of the park excluding cross roads = 200100 m² * (1 hectare / 10000 m²)

Area of the park excluding cross roads = 20.01 hectare

Hmmm i had this before , give me a sec

Answer to your question: a. the fundamental theorem of algebra tells you that the equation will have two complex roots since the degree of the polynomial is 2. the roots are ​ x=1±i7√2 .number of roots=degree of polynomialhere, degree of polynomial is 2 so number of roots will be 2.hope it *_*