Alex was biking on a 48 mile trail, first half of the time he was going twice as fast as the second time, if he spent 4 hours on the road, how fast was he going at first

The speed Alex was going first was 16 mph

Step-by-step explanation:

The distance Alex was walking = 48 mile

The speed with which Alex was walking for the first half of the time = 2 × The speed Alex was walking for the second half of the time

The total time Alex spends on the road = 4 hours

Let x represent the speed with which Alex was walking in miles per hour, (mph), the first half of the time

Therefore, we have;

x × 2 + x/2 × 2 =  48

3·x = 48

∴ x = 48/3 = 16

Therefore, the speed with which Alex was walking in miles per hour, (mph), the first half of the time = x = 16 mph

Alex was going at 16 miles per hour (mph) first.

32/80  

91/140

the last one 54 doesn't go into 45. 54/100 ?

step-by-step explanation: