A polling agency is investigating the voter support for a ballot measure in an upcoming city election. The agency will select a random sample of 500 voters from one region, Region A, of the city. Assume that the population proportion of voters who would support the ballot measure in Region A is 0.47. What is the probability that the proportion of voters in the sample of Region A who support the ballot measure is greater than 0.50

The value is  

Step-by-step explanation:

From the question we are told that

   The sample size is  n =  500

   The  population proportion is  p =  0.47  

Generally given that the sample size is sufficiently large , the mean of this sampling distribution is mathematically represented as

Generally the standard deviation of the sampling distribution is mathematically represented as

=>    

=>    

Gnerally the probability that the proportion of voters in the sample of Region A who support the ballot measure is greater than 0.50 is mathematically represented as

=>        

From the z table  the area under the normal curve to the left corresponding to  1.3453   is

So  

answer: y = -12x + 108

step-by-step explanation: do (y = m x+b) formula.

answer: 230 miles ( vote ! )

step-by-step explanation:

180.39 minus 17.99 equals 162.4

then divide 162.4 by .80 to get 230