Solve the system using substitution.
X + 5y = 0
3y + 2x = -21
([?], 1)

(-15, 3)

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets Parenthesis Exponents Multiplication Division Addition Subtraction Left to Right

Equality Properties

Algebra I

Solving systems of equations using substitution/elimination

Step-by-step explanation:

Step 1: Define Systems

x + 5y = 0

3y + 2x = -21

Step 2: Rewrite Systems

x + 5y = 0

Subtract 5y on both sides:          x = -5y

Step 3: Redefine Systems

x = -5y

3y + 2x = -21

Step 4: Solve for y

Substitution

Substitute in x:                     3y + 2(-5y) = -21Multiply:                                3y - 10y = -21Combine like terms:             -7y = -21Isolate y:                                y = 3

Step 5: Solve for x

Define equation:                    x + 5y = 0Substitute in y:                       x + 5(3) = 0Multiply:                                  x + 15 = 0Isolate x:                                 x = -15

Magic man is here, but unfortunately he is broke won’t you him out