a bag contain 10 marbles: 4 are green, 4 are red and 2 blue. martina chooses a marble at random and without putting it back, choose another one at random, what is the probability that the first marble is blue and the second is green, write your answer as a fraction in simplest form

The probability that both marbles she chooses are blue is 2/15 Step-by-step explanation: Given: A bag contains 10 marbles: 4 are green, 2 are red, and 4 are blue. Christine chooses a marble at random, and without putting it back, chooses another one at random.
To find: What is the probability that both marbles she chooses are blue? Solution : Total number of marbles = 10 Green bles = 4 Red marbles =2 Blue marbles = 4

Probability is favorable outcome upon total number of outcomes.
Probability of getting first marble is blue Pfirst blue marble)= 4/ 10 = 2/ 5.
Without replacement,
i.e. Blue marble left = 3 Total marble left = 9
Probability of getting second marble is blue P(second blue marble)= 3/9 = 1/3 The probability that both marbles she chooses are blue is P(both blue marble)= 2/5 * 1/3 P(both blue marble)= 2 /15.
Therefore, probability that both marbles she chooses are blue is 2/15

38+105= 143, 39+104=143, and you will find then adding the numbers on opposite sides, moving inwards yields the answer 138 every time. because of this, you’re going to multiply 138 times the number of pairs, which is 34. therefore, 34*138= 4692(i’m sorry if it’s the wrong numbers, but it’s the right concept)