solve In 2010, the percentage of assisted living residents who had both heart disease and depression was 9%, the percentage with only heart disease was 25%, and the percentage with either condition was 48%. What percentage of assisted living residents had only depression

The percentage of assisted living residents had only depression

P(D) =0.32

Step-by-step explanation:

Explanation:-

Given  the percentage of assisted living residents who had both heart disease and depression was 9%

Let The event 'H' be the event of heart disease and 'D' be the event of depression

P(H ∩D) = 9% =0.09

The  percentage with only heart disease was 25%

P(H) = 0.25

The percentage with either condition was 48%.

P(H∪D) = 48%=0.48

By addition theorem on probability

            P(D) = 0.48 -0.16

            P(D) = 0.32  

The percentage of assisted living residents had only depression

P(D) =0.32

the answer is b: 18

step-by-step explanation:

use the pythagorean theorem to .

a^2+b^2=c^2

plug 18 for "r"

the 2 legs are 18 and 24

18^2+24^2=c^2

324+576=c^2

900=c^2

c=30

30-12=18

18 is the radius

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