WILL GIVE BRAINLIST AND PLS INCLUDE HOW YOU SOLVED IT! The relationship between altitude and the boiling point of a liquid is linear. At an altitude of 8200 it, the liquid boils at
195.42°F. At an altitude of 4300 ft, the liquid boils at 202.83F. Write an equation giving the boiling point b of the liquid,
in degrees Fahrenheit, in terms of altitude a, in feet. What is the boiling point of the liquid at 2500 it?
Write an equation

b = -0.0019a + 211

at a=2500, b=215.75

Step-by-step explanation:

The points we get from the problem are

(8200 , 195.42)

(4300, 202.83)

where a= altitude and b=boiling point in degrees F

to find slope by b2-b1 / a2-a1

(202.83 - 195.42) / (4300-8200)

= 7.41 / -3900

= -0.0019

we have b = -0.0019a + intercept

substitute in one point to figure out intercept

195.42 = -0.0019(8200) + intercept

195.42 = -15.58 + intercept

add 15.58 to both sides

195.42 + 15.58 = -15.58 + 15.58 + intercept

intercept = 211

b = -0.0019a + 211

At an altitude of 2500ft (a=2500) find b.

b = -0.0019(2500) + 211

b = 4.75 + 211 = 215.75

b = 215.75 degrees F

please give thanks by clicking heart button :)

the two may have that, even a breakdown is probably offered

the equation cos(35) =a/25 can be used to find the length of bc what is the length of bc? round to the nearest tenth

step-by-step explanation: