Suppose that scores on a particular test are normally distributed with a mean of 140 and a standard deviation of 18. What is the minimum score needed to be in the top 5% of the scores on the test? Carry your intermediate computations to at least four decimal places, and round your answer to one decimal place.

153.16

Step-by-step explanation:

We solve using z score formula

z = (x-μ)/σ, where

x is the raw score = ???

μ is the population mean = 140

σ is the population standard deviation = 8

Top 5% means the score is in the 95th percentile

The z score of 95th percentile = 1.645

1.645 = x - 140/8

Cross Multiply

1.645 × 8 = x - 140

13.16 = x - 140

x = 13.16 + 140

x = 153.16

Therefore, the minimum score needed to be in the top 5% of the scores on the test is 153.16

option a is correct.

step-by-step explanation:

scale factor: it is used to find proportional measurements.

proportions means having the same ratio.

scale factor is the ratio of the model measurement to the actual measurement in a simplest form.

or we can say that the ratio of any two corresponding lengths in two similar geometric figures

if the scale factor is more than 1, then it is an enlargement,

if the scale factor less than 1, then it is a reduction.

given the two geometric figure:

by definition of proportions, we have