A marketing researcher conducts a test to determine whether the number of chocolate chips per cookie differs significantly across two brands of chocolate chip cookies. A random sample of 10 Chewy Delight cookies reveals a mean of 6.4 chocolate chips per cookie and a standard deviation of 1.1 chocolate chips per cookie. A random sample of 11 Chips Destroy cookies reveals a mean of 5.6 chocolate chips per cookie and a standard deviation of 1.7 chocolate chips per cookie. Assuming unequal population variances, what is the calculated value for the associated test statistic?

the value for the associated test statistic is 1.2653

Step-by-step explanation:

Given that;

sample size one n₁ = 10

mean one x"₁ = 6.4

standard deviation one S₁ = 1.1

sample size two n₁ = 11

mean two x"₂ = 5.6

standard deviation one S₁ = 1.7

H₀ : μ₁ = μ₂

H₁ : μ₁ ≠ μ₂

Pooled Variance

sp = √( { [(n₁ - 1) × s₁² + (n₂ - 1) × s₂²] / (n₁ + n₂ - 2)} × (1/n₁ + 1/n₂))

we substitute

= √( { [(10 - 1) × (1.1)² + (11 - 1) × (1.7)²] / (10 + 11 - 2)} × (1/10 + 1/11))

= √( { [(9) × 1.21 + (10) × 2.89]  / (19) } × (0.1909))

= √({[ 39.79 ]  / 19} × (0.1909))  

= √( 2.0942 × 0.1909)

= √( 0.39978 )

= 0.63228

Now Test Statistics will be;

t = ( x"₁ - x"₂) / sp

we substitute

t = ( 6.4 - 5.6) / 0.63228

t = 0.8 / 0.63228

t = 1.2653

Therefore the value for the associated test statistic is 1.2653

arc length = 6.63311 ft.

step-by-step explanation:

the formula the arc measure is:

arc length s=2πr(c)/360

where:

c   is the central angle of the arc in degrees

r   is the radius of the arc

π   is pi, approximately 3.142

using the above formula we get

s =

thus we find that arc length of an arc for a circle of radius 20 feet and central angle 19 degrees is

6.63311 feet