A) Find the values of k for which the equation x 2 − 2(2k + 1)x + (k + 2) = 0 has 2 equal roots.

Step-by-step explanation:

For a quadratic equation to have 2 equal root, the discriminant value must be equal to zero.

Discriminant D = b² - 4ac = 0

Given the equation

x^2 − 2(2k + 1)x + (k + 2) = 0

From the equation, a  = 1, b = -2(2k+1), c = k+2

a = 1, b = -4k - 2, c = k+2

Substitute into the discriminant formula;

Recall that: b² - 4ac = 0

(-4k - 2)²-4(1)(k+2) = 0

16k²+16k + 4 - 4k - 8  =0

16k²+12k - 4 = 0

16k²+16k - 4k - 4 = 0

16k(k+1)-4(k+1) = 0

16k - 4 = 0 and k+1 = 0

16k = 4 and k = -1

k = 4/16 and k = -1

k = 1/4 and -1

Hence the required value of k is 1/4 and  -1

we know that

major arc is defined as the bigger arc connecting two points on the edge of a circle. measure of major arc is always more than ° or π radian

in this problem

the mayor arc is bac

find the ratio of the measure of the major arc to the measure of the minor arc

therefore

the answer is the option