The base of a rectangular solid is 4ft. long and 3ft. wide. what is the volume of the solid if its diagonal is sqrt of 41 ft.?

The diagonal of the figure forms a right angle triangle with the diagonal of the base and the height of the figure.
Diagonal of base = √(3² + 4²)
= 5ft
Diagonal of solid² = Diagonal of base² + height²
height = √((√41)² + 5²)
height = 8.12 feet
Volume = width x length x height
Volume = 3 x 4 x 8.12
= 97.44 cubic feet

the image of (6, 9) under a dilation is (4, 6). the scale factor is

b. 2/3

Ithink the answer may be -7 by when dividing both sides by -3