Dimas is playing a game that uses a number cube. The sides of the cube are labeled from 1 to 6. Dimas wants to roll a 2 or 3. He rolls the number cube one time

B. 1/3

Step-by-step explanation:

The total number of sides in the cube are 6 (1,2,3,4,5,6). If Dimas only wants to roll either a 2 or 3 then that would mean that he has 2 chances out of the total 6 probable outcomes to roll one of those numbers. Therefore, in order to find the probability of this happening in a single roll we need to divide the number of times that his two choices appear on the dice by the total number of sides the dice has, like so...

2 / 6 = x

If we simplify it would give us

understand that i don't know the answers

will someone answer his question