If nitrogen is warmer than -320^\circ−320 ∘
minus, 320, degrees Fahrenheit, it will be a gas.
Write an inequality that is true only for temperatures (t)(t)left parenthesis, t, right parenthesis at which nitrogen is a gas.

i am unable to solve this problem

step-by-step explanation:

b. 1.25 hr

step-by-step explanation:

if you have a constant speed of 60 mph, then you have a ratio between 60 mi. to 1 hr. dividing both sides by 60 we get the ratio

1 mi. to

then mult. both sides by 75 we get the ratio

75 mi. to

simplifying we get

75 mi. to

or 1.25 hr.

check above link.

graphically?   well, you graph them both, the solutions is where they both intersect each other, since there are two solutions, meaning they will meet twice, or namely the linear will run into the quadratic curve twice, and where they meet, those x,y coordinates are the solutions to the system.

answer: i believe the answer is e

step-by-step explanation: