Find the values of x in [0, 360°) which satisfy the
equation below.
2 cota x = -3 SC X

Given :

An equation 2cot x = -3sec x .

To Find :

the values of x in [0, 360°) which satisfy the given equation.

Solution :

Converting cot x and sec x in the form of sin x and cos x.

Neglecting sin x = 2 because sin x cannot be greater than 1.

x = π - π/6, π + π/6

x = 5π/6 and x = 7π /6

Therefore, the values of x in [0,360°) is  5π/6 and x = 7π /6 .

the equation for this situation is y=122+45. to solve the equation you would add 45 and 122 to get a total of 167lbs. in conclusion, grace's weight eight weeks ago was 167lbs.