The sum of the digits of a three-digit number is 12. The tens digit, t, is 2 more than the hundreds digit, h. The units digit, u, is equal to the sum of the tens and hundreds digits. What is the number?

so the equation would be

u+t+h=12

lets break it down

we know that t is equal to

h+ 2

and we know that u is equal to

h+t

okay so first we need to focus on finding one of the units then we can find the next ones

so lets find h first,

with the equations we found h is involved in all of them so we can use them in the equation that equals 12 ( ill make it easier for you and make all of the units equal to their equation including h)

u= h+t

h+2=t

t= h+2

h=h

u= h+h+2

so lets put it together

(h+h+2)+(h)+(h+2)=12

4h+4=12

    -4  -4

4h=8

/4   /4

h=2

okay now using our other equations lets find t and u

h+2=t

2+2=t

4=t

h+t=u

2+4=u

6=u

now lets check our answers

u+t+h

6+4+2=12

10+2=12

12=12

so now that we know the values lets put them into their places in the number

uth

u=6

t=4

h=2

642 is your number

if you need anymore clarification just ask or help with another problem

Step-by-step explanation:

the correct answer is 5