A cup of coffee has coded from 92°C to 50°C Cefter 12 min in a room at 22°C. How long will the cup take
to cool to 30°C

According to my calculations the cup had dropped 42°C in 12 minutes so that is equivalent to 3.5°C each minute if im not mistaken the cup is now at 22°C and needs to be warmed back up to 30°C that is a little odd but i multiplied 3.5 and the amount on minutes 22 is from 30 to get 8 so this would take a weeping 28 minutes.

kinda confusing cause the degrees is off

let's call the solutions x₁ = (5 - 2√7)/3 and x₂ = (5 + 2√7)/3

then the equation is (x-x₁)(x-x₂) = 0

if you fill that in you get a lot of numbers which you can recognize as ax²+bx+c=0.

step-by-step explanation:

you can see that a=1 (there is just an x²)

b = (-5 -2√7 + 2√7 - 5)/3 = -10/3

c = -2√7)/3 ) * (-5+2√7)/3) = -1/3

so your answer is 3x^2 – 10x – 1 = 0