WILL MARK BRAINLIEST Find three consecutive even integers such that the sum of the second and third is 3 times the first integer.

3, 4, and 5

Step-by-step explanation:

Given: We're looking for x, x+1, and x+2

Requirements: (x+1)+(x+2)=3(x)

Solve equation:

x+1+x+2=3x

2x+3=3x

3=x

This means the three consecutive integers are 3, 3+1, and 3+2 which is the same as 3, 4, and 5

the answer to your question a or b but i am pretty sure it is b. i hope this : )

step-by-step explanation: