Monitors manufactured by TSI Electronics have life spans that have a normal distribution with a standard deviation of 15001500 hours and a mean life span of 16,00016,000 hours. If a monitor is selected at random, find the probability that the life span of the monitor will be more than 18,09918,099 hours.

0.0809

Step-by-step explanation:

Given that :

Mean(m) = 16000

Standard deviation (s) = 1500

Probability that the life span of the monitor will be more than 18,099

P(x > 18099)

Using the Zscore formula :

Zscore =(x - m) / s

Zscore = (18099 - 16000) / 1500

Zscore = 2099 / 1500

Zscore = 1.399

P(Z > 1.399)

Using the Z probability calculator :

P(Z > 1.399) = 0.080906

= 0.0809

26

step-by-step explanation:

d, x=8

step-by-step explanation:

simplifying

4x + -5 = 2x + 11

reorder the terms:

-5 + 4x = 2x + 11

reorder the terms:

-5 + 4x = 11 + 2x

solving

-5 + 4x = 11 + 2x

solving for variable 'x'.

move all terms containing x to the left, all other terms to the right.

add '-2x' to each side of the equation.

-5 + 4x + -2x = 11 + 2x + -2x

combine like terms: 4x + -2x = 2x

-5 + 2x = 11 + 2x + -2x

combine like terms: 2x + -2x = 0

-5 + 2x = 11 + 0

-5 + 2x = 11

add '5' to each side of the equation.

-5 + 5 + 2x = 11 + 5

combine like terms: -5 + 5 = 0

0 + 2x = 11 + 5

2x = 11 + 5

combine like terms: 11 + 5 = 16

2x = 16

divide each side by '2'.