The pencils produced by the machine are unsharpened, so two employees in the factory need to sharpen each pencil by hand. Employee A can sharpen 8 pencils per minute and Employee B can sharpen 5 pencils per minute. Employee A breaks 10% of the pencils they sharpen and Employee B breaks 15% of the pencils they sharpen. What is the probability that a broken pencil was broken by Employee A

0.4156

Step-by-step explanation:

Given that:

Employer A:

8 pencils per minute

Probability of breaking a pencil = p(A) = 10%

Employer B:

5 pencils per minute

Probability of breaking a pencil = p(B) = 15%

Hence,

Probability of breaking a pencil:

P(breaking a pencil) = (P(A breaks pencil) * P(A)) + (p(B breaks pencil) * p(B))

P(A breaks pencil) = 0.1 * 8 = 0.8

P(B breaks pencil) = 0.15 * 5 = 0.75

P(breaking a pencil) = (0.8 * 0.1) + (0.75 * 0.15) = 0.1925

Hence, probability that a broken pencil was broken by employer A will be :

(P(A breaks pencil) * P(A)) / probability of breaking a pencil

= (0.8 * 0.1) / 0.1925

= 0.08 / 0.1925

= 0.4155844

= 0.4156

answer: ok

step-by-step explanation:

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