If (x+2) is a factor of 3x^2-4kx-4k^2, then find the value(s) of k

The values of k will be:

Step-by-step explanation:

Let the expression of polynomial P be

Let the expression if the polynomial Q be

Plug in Q(x) = 0

0 = x+2

x = -2

As (x+2) is a factor of 3x²-4kx-4k²

substitute x = -2 in the the polynomial

3x²-4kx-4k² = 0

Write in the standard form ax²+bx+c = 0

Factor out common term -4

Factor k²-2k-3: (k+1)(k-3)

Using the zero factor principle

if ab=0, then a=0 or b=0 (or both a=0 and b=0)

solving k+1=0

k+1 = 0

k = -1

solving k-3=0

k-3=0

k = 3

Thus, the values of k will be:

the equation for this situation is y=122+45. to solve the equation you would add 45 and 122 to get a total of 167lbs. in conclusion, grace's weight eight weeks ago was 167lbs.  

answer:   c ?

step-by-step explanation: