A collection of quarters and dimes has a total value of $5 and contains 32 coins. How many of each kind of coin are in the collection?

Step-by-step explanation:

Let q be the number of quarters and d be the number of dimes.

We have q + d = 32 and $0.25q + $0.10d = $5.

=> 5q + 2d = 100 and q + d = 32

Therefore we get q = 12 and d = 20. (12 quarters and 20 dimes)

step-by-step explanation:

let y equal to

the total fare and x is the mile of taxi ride. so the equation is

y = 0.55x + 1.75

since susie has

$10 to spend for a taxi cab, so he can have

10 = 0.55x +

1.75

x = 15 miles of

taxi ride

so the system of

inequality is

10 < 0.55x +

1.75

x > 2