Find the distance from a vector (2; 3; 1)T to the subspace spanned by the vectors (1; 2; 3)T , (1; 3; 1)T . Note, that I am only asking to nd the distance to the subspace, not the orthogonal projection.

7

step-by-step explanation:

step-by-step explanation:

6.48/4 4 goes into 6.48 1.62 times

u = -(6/7)w

step-by-step explanation:

place all values with 'u' on one side of the equation.

4u + 8w = - 3u + 2w

4u + 3u = 2w - 8w

further simplify the equation by solving the addition and subtraction.

7u = - 6w

make 'u' the independent variable by placing its co-efficient on the right-hand side.

u = - (6/7)w