A sector with an area of \goldE{26\pi\,\text{cm}^2}26πcm 2 start color #a75a05, 26, pi, start text, c, m, end text, squared, end color #a75a05 has a radius of \maroonD{6\,\text{cm}}6cmstart color #ca337c, 6, start text, c, m, end text, end color #ca337c. What is the central angle measure of the sector in radians?

13π/9 rad

Step-by-step explanation:

Given the following

Area of a sector = 26πcm²

radius of the sector = 6cm

Required

central angle measure of the sector in radians

Area of a sector = Ф/2π * πr²

26π = Ф/2π * πr²

26 = Ф(6)²/2π

26 = 36Ф/2π

2π = 36Ф/26

π = 18Ф/26

26π = 18Ф

Ф = 26π/18

Ф = 13π/9 rad

Hence the measure of the central angle in radians is  13π/9 rad

hope this !

step-by-step explanation:

d = distance between moon and sun, which in this problem is the hypotenuse of a right triangle.  

the distance y is the side opposite to angle x in the right triangle.   use the definition of the sine function from basic trigonometry.

sin(x) = y/d ⇒

d = y/sin(x)

it’s supposed to be -4+45=41

step-by-step explanation: