A company sells two electronics packages. Package A contains 4 printers and 9 computers and costs $10,100 Package B contains 10 printers and 30 computers and costs $36,000

y = $1433.33

x = -$700

Step-by-step explanation:

Since we are not asked what to find, we can as well find the price of each package.

Let x be the price of one printer

Let y be the price of one computer.

If Package A contains 4 printers and 9 computers and costs $10,100, this is expressed as;

4x + 9y = 10,100 1

If Package B contains 10 printers and 30 computers and costs $36,000, this is expressed as;

10x + 30y = 36,000

x + 3y = 3600 2

Solve equation 1 and 2 simultaneously

From 2; x = 3600 - 3y 3

Substitute 3 into 1;

From 1;

4x + 9y = 10,000

4(3600-3y) + 9y = 10,100

14400 - 12y + 9y = 10100

14400 - 3y = 10100

-3y = 10100 - 14400

-3y = -4300

y = 4300/3

y = $1433.33

Substitute y = 1433.3 into 2;

From 2: x+3y = 3600

x + 3(1433.33) = 3600

x+4300 = 3600

x = 3600 - 4300

x = -$700

i believe that the answer is

b. y-1=-2(x-4)

hope this !

570, the answer is 570, hope it