If the 3rd term of a geometric series is -3 and the sum of the 4th term and the 5th term is –6, find the 7th term of the series.

if the eqn of the parabola is f(x) = (x-4)(x+2), we need to mult. this out to find the coordinates of the vertex.

then f(x) = x^2 + 2x - 4x - 8, and f(x) = x^2 - 2x - 8.

one way in which you can find the vertex is to calculate x = -b / (2a).   here, that comes to

        )

x = = 1.   f(1) = 1^2 - 2(1) - 8 = - 9.   vertex is at (1, -9).

        2(1) 

find another point on the curve:   let x=0, for which y=-8.   then (0, -8) is on the curve.   plot the vertex and this point and draw a smooth parabola thru both.

hope this

sum= when you add is how much the whole amount is

distance= when you use angles and it means how far it goes

step-by-step explanation:

the reason why your question keeps getting deleted because this is not a school related question : )

i will answer your question though.

i never tried church's

the correct answer is x/3+10≥32

hope this !