The radius r of a sphere is increasing at a constant rate of 0.04 centimeters per second. (Note: The volume of a sphere with radius r is V=4/3 pi r³.) At the time when the radius of the sphere is 10 centimeters, what is the rate of increase of its volume?

The rate of the volume increase will be

Step-by-step explanation:

Let's take the derivative with respect to time on each side of the volume equation.

Now, we just need to put all the values on the rate equation.

We know that:

dR/dt is 0.04 cm/s  

And we need to know what is dV/dt when R = 10 cm.

Therefore using the equation of the volume rate:

I hope it helps you!

step-by-step explanation:

given perimeter: 28cm

length: 9cm

atp,

2(l+w)=p of the reactangle

2(9+x)=28

18+2x=28

2x=28-18

x=10/2

x=5

therefore width is 5 cm

lol.

it's ok we all do this sometimes.

-aparri