Suppose babies born in a large hospital have a mean weight of 3831 grams, and a variance of 108,900. If 65 babies are sampled at random from the hospital, what is the probability that the mean weight of the sample babies would differ from the population mean by less than 45 grams

the probability that the mean weight of the sample babies would differ from the population mean by less than 45 grams is 0.7284

Step-by-step explanation:

Given that

mean weight = 3831 grams,

variance = 108,900

sample size n = 65

the probability that the mean weight of the sample babies would differ from the population mean by less than 45 grams = ?

Now standard error of mean = √( 108900 / 65 ) = 40.9314

z = +/- (45/40.9314)

z = +/-1.0994

so

P( -1.0994 <z< 1.0994 ) = P( z<1.0994 ) - (p<-1.0994 )

= 0.8642 - 0.1358

= 0.7284

Therefore the probability that the mean weight of the sample babies would differ from the population mean by less than 45 grams is 0.7284

answer is d-29

step-by-step explanation:

since you didn't include the picture, i can give you the description so you know how to pick the correct answer. the third quartile of a data is always shown in a box plot. in the middle of your graph should be a box. the third quartile is the value that goes with the far right edge of the box.

step-by-step explanation:

goog be able to you with that maybe