Another reverse percentages question. i tried doing a method i learnt but got 19.2-which is not correct. during a promotion a bag of sweets contain 20% extra free. There are 24 sweets in the bag during the promotion.
How many sweets are there normally?

Given:

During a promotion a bag of sweets contain 20% extra free.

Sweets in the bag during the promotion = 24

To find:

The number of sweets are there normally.

Solution:

Let x be the number of sweets are there normally.

Then, number of sweets during the promotion is 20% more than x.

Sweets in the bag during the promotion = 24

Multiply both sides by 5.

Divide both sides by 6.

Therefore, normally there are 20 number of sweets.

the 4th choice is the correct one

step-by-step explanation:

3-4

step-by-step explanation:

the answer is 3-4 because both 45 and 60 has a multiple of 15.

45/3=15

60/4=15

therefore the odds against selecting a red is 4-3