For your trouble answering this, you will get 30 points. for all the trouble this may cause. A: 2 cups concentrate, 3 cups of cold water
B: 5 cups concentrate, 9 cups of cold water
C: 1 cup concentrate, 2 cups of cold water
D: 3 cups concentrate, 5 cups of cold water.

A1: which mix will make juice that is the most "orangey"? explain your reasoning.
A2: Which mix will make juice that is the least "orangey"? explain your reasoning.

C: assume that each camper will get ½ cup of juice. answer questions (1) and (2) below for each of the four recipes.

1: how many batches are needed to make juice for 240 campers?
2: How much concentrate and how much water is needed to make juice for 240 campers?

read below

Step-by-step explanation:

A1: I think D because you have a medium average mix of concentrate that will mix with only 2 more cups than itself, so this would keep it fine. A could also work s A or D. i dont know at this point. B COULD be a possible solution but it's 5 vs 9.

A2: C

1 cup of concentrate vs 2 water the water will make it MUCH more of a clear color.

Question C: this is more time consuming and I am tired so for you this might be easier if you're not as tired so based on what I'm reading you need to do math for each of the 4 options above, concentrate and water mix, and then divide the total of the 2 types of cups for every option.

Hope Q1 and Q2 helped though!

answer: x

step-by-step explanation:

part a

answer: a reasonable domain is where n is a real number. so n can be between 0 and 10. both endpoints are included.

work shown:

n is the number of days after the experiment starts. the smallest n can be is n = 0 which means that 0 days have gone by, and we're at the start. to find out how large n should be, then replace f(n) with 16.13 and solve for n. use logarithms to isolate the exponent.

f(n) = 12*(1.03)^n

16.13 = 12*(1.03)^n

16.13/12 = (1.03)^n

1.34416666666667 = (1.03)^n

(1.03)^n = 1.34416666666667

log[ (1.03)^n ] = log[ 1.34416666666667 ]

n*log[ 1.03 ] = log[ 1.34416666666667 ]

n = log[ 1.34416666666667 ]/log[ 1.03 ]

n = 10.0062999823929

this rounds to n = 10 which is fairly close but not 100% perfect. so this is the largest n can be.

note: if you plug n = 10 into f(n), you'll get roughly 16.127 which rounds to 16.13 (this comes up again in part c)

=====================================

part b

answer: the y intercept is 12. it represents the starting height of the plant in cm.

work shown:

plug n = 0 into the f(n) function. simplify

f(n) = 12*(1.03)^n

f(0) = 12*(1.03)^0

f(0) = 12*(1)

f(0) = 12

on day n = 0, aka the starting point, the height f(n) is 12 cm

=====================================

part c

answer: the average rate of change is approximately 0.43061036458991 (round however you need to). this represents the average growth rate from day n = 3 to day n = 10. so the plant grew roughly 0.43 cm per day during this timespan, assuming you round to 2 decimal places.

work shown:

compute f(3)

f(n) = 12*(1.03)^n

f(3) = 12*(1.03)^3

f(3) = 13.112724 < we'll use this later

compute f(10)

f(n) = 12*(1.03)^n

f(10) = 12*(1.03)^10

f(10) = 16.1269965521294 < we'll use this later

now use the formula below with a = 3 and b = 10

aroc = average rate of change

aroc = [ f(b) - f(a) ]/[ b - a ]

aroc = [ f(10) - f(3) ]/[ 10 - 3 ]

aroc = (16.1269965521294 - 13.112724)/(10 - 3)

aroc = 3.0142725521294/7

aroc = 0.43061036458991

round this however you need to

note: the plant grew approximately 3.01 cm over 7 days, so roughly 0.43 cm per day is the average growth rate (if you were to round to 2 decimal places).