Algebraically, find all remaining zeros of f(x) = 8x^3 - 6x^2-36x +27 in simplest form.

Step-by-step explanation:

In order to find the zeros of a function, we must first set the equation equal to zero, so we get:

so we can now solve this by factoring. We can factor this equation by grouping. We start by grouping the equation in pairs of terms, so we get:

and factor each group, so we get:

and now factor again, so we get:

and now we set each of the factors equal to zero to find the zeros:

we divide both sides into 2 to get:

and take the square root to both sides to get:

which yields:

We rationalize so we get:

this means that we have two zeros here:

and

so we take the other factor and set it equal to zero.

4x-3=0

and solve for x

4x=3

and that will be our third zero.

step-by-step explanation:

x^2 -12x + 36 + y^2 = 36

x^2 + y^2 = 12x

r^2 = 12rcos(theta)

r = 12 cos(theta)

answer: 7

step-by-step explanation: