Consider the following vectors in component form a= b= c=a-b What is the magnitude and direction angle of vector c?

|c| = 5, θ = 36.9°
|c| = 5, θ = 53.1°
|c| = 25, θ = 16.3°
|c| = 25, θ = 73.7°

(2,6)

step-by-step explanation:

cause i just did this and got the answer

you're welcome

where is the graph? need more info

choose (5, 1.5) and (-1.5,-3.5)

step-by-step explanation:

5 - 1.5 =3.5

-1.5 - (-3.5) = 2

3.5 + 2 =5.5

hope this !

1. 16.64

a^2+b^2=c^2

pr^2=pq^2+qr^2

pr^2=14^2+ 9^2

pr^2=196+81

pr= sqr root of 277

16.64

2. 11.31

c^2-a^2=b^2

18^2- 14^2=b^2

b^2=324-196

b=sqr root of 126

b=11.31

hope it ! (btw im in connections academy to, good luck! )