Suppose a random sample of 50 college students are asked to measure the length of their right foot in centimeters. A 95% confidence interval for the mean foot length for students at the college is found to be 21.709 to 25.091 cm. If a 99% confidence interval were calculated instead, how would it differ from the 95% confidence interval

A  99% confidence interval  will be wider than a 95% confidence interval

Step-by-step explanation:

From the question we are told that

  The  95% confidence interval for for the mean foot length for students at the college is found to be 21.709 to 25.091 cm

Generally the width of a confidence interval is dependent on the margin of error.

Generally the margin of error is mathematically represented as  

From the above equation we see that

Here    is the critical value of the half of the level of significance and this value  increase as the confidence level increase

Now if a  99% confidence level is  used , it then means that the value of  

   will increase, this in turn will increase  the margin of error and in turn this will increase the width of the confidence interval

Hence a 99% confidence interval  will be wider than a 95% confidence interval

x= -3

step-by-step explanation:

step 1: simplify brackets

4 - x - 1 = 6

step 2: simpilfy

3 - x = 6

step 3: subtract 3 from both sides

-x = 6 - 3

step 4: simpilfy 6 - 3

-x = 3

step 5: multiply both sides by -1

x = -3

b is 38 degrees.

a is 52 degrees.

this is because if b is 38 and a is 14 degrees more than b than 38+14=52 and 52+38=90 degrees. hope this .