The height in feet of an object projected upward as a function of the elapsed time in seconds since it was launched can be represented by the formula shown below. h(t) = –16t2 + v0t + h0 In the formula h(t) is height in feet; t is time in seconds; v0 is the initial velocity; and h0 is the initial height. An object is projected upward with an initial velocity of 50 feet per second from a starting height of 9 feet. When will the object hit the ground?

step-by-step explanation:

i think something is missing in your question because y-1=(x-12) would not pass through the point (-4,-3). because if you replace x by -4 your are supposed to find y=-3 which is not the case her. if you replace x by -4 you find =-15.

i assume the right equation is y-1=1/4*(x-12) because this one is passing through both your points (if you are interested to know how i found that out i can tell you).

in this equation if i replace x by -4 i find y=-3 and if i replace x by 12, i find y=1 so the line representing this equation is passing through those 2 points.

then the standard form of the equation is finding an expression of y in function of x

y-1=1/4*(x-12)

y=x/4-3+1

y=x/4-2

hope that .

do you confirm there was a mistake in the question?

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