A recent study of 26 city residents showed that the time they had lived at their present address has a mean of 10.3 years with the standard deviation of 3 years. Find the 95% confidence interval of the true mean. Assume that the variable is approximately normally distributed.

The 95% confidence interval is  

Step-by-step explanation:

From the question we are told that

     The sample size is  n =  26

      The mean is  

       The standard deviation is  

From the question we are told the confidence level is  95% , hence the level of significance is    

=>  

Generally from the normal distribution table the critical value  of   is  

Generally the margin of error is mathematically represented as  

=>  

=>  

Generally 95% confidence interval is mathematically represented as  

=>  

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