Find the third side in simplest radical form:

a^2 + b^2 = c^2 (pythagorean theorem)

a^2 + 40^2 = 41^2 (plug in the known values)

a^2 + 1,600 = 1681  (simplify what you can)

a^2 = 81 (subtracted 1600 from both sides)

a= (81 under a radical) (I think this is what your answer will be, based on the problem)

a=9 (what the fully simplified answer is)

(2x + 16) + (x) = 180

step-by-step explanation:

given,

abcd is a quadrilateral inscribed in a circle

angle a is labeled x plus 16, (x + 16)

angle b is labeled x degrees, (x)

angle c is labeled 6x minus 4, (6x – 4)

angle d is labeled 2x plus 16, (2x + 16)

what equation can be used to solve for angle b?

we know that the sum of the opposite angles of a simple quadrilateral inscribed in a circle is 180 degrees.

angle b is opposite angle d

therefore, angle b + angle d = 180

(x) + (2x + 16) = 180 

same as (2x + 16) + (x) = 180

idk

step-by-step explanation: