Find the volume of a region bounded by the functions y = 2x + 6, the y-axis, and the x-axis as it revolves around the x-axis.
GRAPH !
V=
units3
(round to the nearest tenth)

The bounded region in question is a triangle in the second quadrant. The line y = 2x + 6 has intercepts (0, 6) and (-3, 0), so revolving the triangle about the x-axis forms a cone with height 3 and whose circular base has radius 6. Its volume would then π/3 • 6² • 3 = 36π ≈ 113.1 units³.

But you're probably supposed to use calculus. Using the disk method, the integral for the volume is

as expected.

i think the answer is .36

step-by-step explanation:

what i did was only 2.88 divided by 8

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