At a college bookstore, Tanisha bought a Math Textbook and a Novel for $54. If the price of the Math Textbook is $8 more than 3 times the price of the Novel, then how much is the price of each book?

Price of Math Textbook= $42.5,  Price of the Novel= $11.5

Step-by-step explanation:

Let x = price of the Novel.

Price of Math Textbook = 8+3x

As per given , we have

Price of Math Textbook + Price of the Novel = $54

⇒ 8+3x+x = 54

⇒ 8+4x=54

⇒ 4x = 46     [subtract 8 from both sides]

⇒ x = 11.5

Price of Math Textbook = 8+3(11.5) = 8+34.5= $42.5

Hence, Price of Math Textbook= $42.5,  Price of the Novel= $11.5

the answer is 200

step-by-step explanation:

the way the question is worded, it seems to imply the $264 interest is simple interest, not compound interest.

the simple interest for 2 years is $264; the simple interest for 1 year is $132.

$132 interest on a $600 investment means an interest rate of (132/600)*100 = 22%.

the value of $200 at 22% interest compounded annually for three years is

200%281.22%29%5e3

the amount of interest is that value, minus the original $200.