What are the solutions of the following system?
x^2+y^2=25
2x+y=-5
a. (0, –5) and (–5, 5)
b.(0, –5) and (5, –15)
c.(0, –5) and (–4, 3)
d.(0, –5) and (4, –13)

Option C is correct

the solution for the given system of equation is, (0, -5) and (-4, 3)

Step-by-step explanation:

Using identity:

Given the equation:

       .....[1]

              .....[2]

We can write [2] as:

Substitute this in [1] we have;

Using identity rule;

Combine like terms;

Subtract 25 from both sides we have;

⇒

By zero product property we have;

x = 0 and x+4 = 0

x = 0 and x = -4

Substitute these in [2] we have;

for x = 0

2(0)+y = -5

⇒

For x = -4 ,

-8+y = -5

add 8 to both sides we have;

y = 3

Therefore, the solution for the given system of equation is, (0, -5) and (-4, 3)

solution:

as, mean is defined as sum of all the observations divided by total number of observations.

and , median is mid value of the data whether arranged in ascending order or descending order.

consider, roadsters:

2,3,4,5,6,7,8,9

mean =

also, median= , because number of observations is even, so median is mean of two mid values.

now, coming to bandits

2,3,4,5,6

mean =  

median = 4, as number of observations is odd.

so, roadsters has greater median as well mean than bandits.

→option a is true about the repairs performed on 2 types of cars:

bandits have lower median and mean than roadsters.

you didn't post any answer choices, so its not 100% clear what your teacher is looking for

however, log(15/7) is equivalent to log(15) - log(7)

i'm using the rule log(x/y) = log(x) - log(y)